2w^2+6w-135=0

Solution for 2w^2+6w-135=0 equation:

2w^2+6w-135=0

a = 2; b = 6; c = -135;
Δ = b2-4ac
Δ = 62-4·2·(-135)
Δ = 1116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1116}=\sqrt{36*31}=\sqrt{36}*\sqrt{31}=6\sqrt{31}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{31}}{2*2}=\frac{-6-6\sqrt{31}}{4}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{31}}{2*2}=\frac{-6+6\sqrt{31}}{4}
$